1 Find the vertex of the function, 𝑓 (𝑥) = 𝑥 2 − 4𝑥 − 12 2 For the function, 𝑓 (𝑥) = 𝑥 2 4𝑥 − 12 Find a) Vertex b) yintercept c) xintercept (s) d) Draw the graph 3 For the linear functions 𝑓 (𝑥) and 𝑔 (𝑥), 𝑓 (1) = 2, 𝑓 (3) = 5 and 𝑔 (4) = 10 Given that 𝑓 (𝑥) and 𝑔 (𝑥) areAnswer (1 of 3) Two ways I am going to do this Completing the square y=x^24x5————(1) y=(x2)^2–45 y=(x2)^21 The vertex is (2,1) Or find the derivative of y with respect to x dy/dx=2x4 When dy/dy=0 , the vertex , 2x4=0 Therefore x=2 What is the vertex form of the equation?

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Y=x^2+4x-12 vertex form
Y=x^2+4x-12 vertex form-You take half of the number that's with the single x , and add the square of that to both sides Explanation → x2 2⋅ (−2)x(−2)2 = 10(−2)2 x24x=192 Two solutions were found x = 16 x = 12 Rearrange Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation Algebra 2 1What is the vertex from the equation?




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Selesaikan masalah matematik anda menggunakan penyelesai matematik percuma kami yang mempunyai penyelesaian langkah demi langkah Penyelesai matematik kami menyokong matematik asas, praalgebra, algebra, trigonometri, kalkulus dan banyak lagiCompleting the perfect square on the right side of the equation by adding 4 to both sides of the equation 4Y = x^212x4 My work (x^2 12x)4 (x^2 12x 36)4 36 Y= (x36)^2 32 Is this correct?
Find an answer to your question Write y=2x^24x12 in vertex form shuvt shuvt Mathematics High School answered Write y=2x^24x12 inAlgebra Find the Vertex y=x^2x12 y = x2 x − 12 y = x 2 x 12 Rewrite the equation in vertex form Tap for more steps Complete the square for x 2 x − 12 x 2 x 12 Tap for more steps Use the form a x 2 b x c a x 2 b x c, to find the values of a a, b b, and c c a = 1, b = 1, c = − 12 a = 1, b = 1, c = 12Write y = 2x2 4x 12 in vertex form y = 2(x 1)2 10 y = 2(x 2)2 12 y = 2(x 1)2 10 y = 2(x 2)2 1 Get the answers you need, now!
To find the vertex just use the equation x= (b)/(2*a) so the first one would be1) The sides of the triangle shown increase in such a way that (dz/dt=1) and (dx/dt=(3dy/dx)) At the instant when x = 12 and y = 5, what is the value of dx/dt?The vertex (h, k) of the parabola y=3x 2 12x12 is (2, 24) Example 2 Find the vertex of the parabola y=3x 26x1 Solution Given parabola equation y = 3x 26x1 The standard form of a parabola is y=ax 2 bxc By comparing standard form and given parabola equations, we get a = 3, b=6, c = 1 We know that the formula to calculate the x




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Algebra questions and answers;Sketch the graph of the function y = x^2 4x The vertex is The yintercept is The xintercepts are Given the quadratic function f(x) = x^2 2x 12 The xcoordinate of the vertex is (use b/2a) Using the xcoordinate, find the vertexWhat is the vertex form of the equation?



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To change the expression (x2 2x) into a perfect square trinomial add (half the x coefficient)² to each side of the expression Here x coefficient = 2 So, (half the x coefficient)2 = (2/2)2 = 1 Add and subtract 1 to the expression The vertex form of the parabola with vertex (h, k) and axis of symmetry x = h is y = a (x h)2 kYou can find the vertex from both standard and vertex forms manually But the fastest mean will be the vertex form converter To learn how to calculate ##y = x^24x12## Part 1 xintercepts The xintercepts occur at point son the function where ##y=0## So, we need to solve ##x^24x12 = 0## The left side factors fairly easily into ##(x6)(x2)=0## So solution occur when ##x6 = 0 rarr x=6## and ##x2= 0 rarr x=(2)## So the xintercepts are at ##(0,6)## and ##(0,2)## Part 2 vertex of the



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Stepbystep explanation vertex form y=a (xh) ^2k you have your equation in standard form ax^2bxc how to change it vertex x= (b)/2 (a) x= (12)/2 (1) x=6 substitute x into original (standardform) equation to find y vertex y= (6)^212 (6)4Precalculus Find the Vertex y=x^24x4 y = x2 4x 4 y = x 2 4 x 4 Rewrite the equation in vertex form Tap for more steps Complete the square for x 2 4 x 4 x 2 4 x 4 Tap for more steps Use the form a x 2 b x c a x 2 b x c, to find the values of a a, b b, and c c a = 1, b = 4, c = 4 a = 1, b = 4, c = 4Get stepbystep solutions from expert tutors as fast as 1530 minutes Your first 5 questions are on us!




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Multiply it out 4{x^24x12)= 4x^216x48 The x value is b/2a = (16/8)=2 Put that into the equation, and y=4(4)(4)=64Algebra Find the Vertex y=x^24x12 y = x2 − 4x − 12 y = x 2 4 x 12 Rewrite the equation in vertex form Tap for more steps Complete the square for x 2 − 4 x − 12 x 2 4 x 12 Tap for more steps Use the form a x 2 b x c a x 2 b x c, to find the values of a a, b b, and c c a = 1, b = − 4, c = − 12 a = 1, bSelesaikan masalah matematik anda menggunakan penyelesai matematik percuma kami yang mempunyai penyelesaian langkah demi langkah Penyelesai matematik kami menyokong matematik asas, praalgebra, algebra, trigonometri, kalkulus dan banyak lagi



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Question What is the vertex form for the function's y= x^24x6, y=x^22x5, y=6x^210, y= 5x^212, y= 4x^27x, y=2x^2x, y= 2x^25x12?Let's look at one more example In vertex form, (h,k) describes the vertex of the parabola and the parabola has a line of symmetry x = h 36 ⓐ Write x = −4 y 2 − 16 y − 12 x = −4 y 2 − 16 y − 12 in standard form and ⓑ use properties of the standard form to graph the equationVertex form is $$ y = 2 (x 6)^2 – 13 $$ Standard form of given equation is $$ y = 2 x^2 24 x 59 $$ Where, Characteristic Points are Vertex P (6, 13) Yintercept P (0, 59) An online parabola vertex calculator can display a parabola graph with exact values when you substitute the same values for a vertex form equation




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Precalculus Find the Vertex f (x)=x^24x12 f (x) = x2 − 4x − 12 f ( x) = x 2 4 x 12 Rewrite the equation in term of x x and y y f (x) = x2 −4x−12 f ( x) = x 2 4 x 12 Rewrite the equation in vertex form Tap for more steps Complete the square for x 2 − 4 x − 12 x 2 4 xSolve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and moreYou have b=12 and c=4



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Find a quadratic function in the form f(x) = ax^2 bx c whose vertex is (1, 5) and yintercept is 3 Solve the following inequalities Express the solution in interval form x^2 30 greaterthanorequalto 13x x 3/x 4 greaterthanorequalto 0;The vertex is on the axis of symmetry __ the equation is x=b/2a x=4/ (2*1) __ x=2 substituting __ y= (2)^24 (2)12 __ y=16 vertex is (2,16)Question Suppose that f(x) = x^2 4x 12 What is




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Alvin L We need to find the vertex of the parabola, and then we'll also get the axis of symmetry (it will have the same xcoordinate as the vertex)Algebra > Finance> SOLUTION what is the vertex of y=4(x2)(x6)?2) Let f(x) = x^3 − 4 Which of these is the equation for the normal maths



Solution Write Each Function In Vertex Form Sketch The Graph Of The Function And Label Its Vertex 33 Y X2 4x 7 34 Y X2 4x 1 35 Y 3x2 18x 36 Y 1 2x2 5x




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So we know that the x coordinate of the vertex is 2 Then, we just take the equation and plug in x=2, to find the y coordinate y=x^2 4x 12 y=2^2 4*2 12 y=4 8 12 y=16 So the vertex is at (2, 16) For more on how this works, check out this page http//wwwpurplemathcom/modules/grphquad2htm • ReplyFunctionvertexcalculator vertex y=x^{2}2x3 en image/svgxml Related Symbolab blog posts Functions A function basically relates an input to an output, there's an input, a relationship and an output For every input 6 Make sure you solve the equation for y, and that's it!



Solution Suppose That F X X 2 4x 12 A What Is The Vertex Of F B What Are The X Intercepts Of The Graph Of F C Solve F X 12 For X What Points Are On The Graph



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Vertex form y= (x2)^2–12 or y16=(x2)^2 Here's my work The given standard form equation y=x^2–4x12;Precalculusfunctionvertexcalculator en image/svgxml Related Symbolab blog posts Functions One Time Payment $1299 USD for 2 months Weekly Subscription $249 USD per week until cancelled Monthly Subscription $699 USD per month until cancelledFind the Vertex Form y=2x^24x12 y = 2x2 − 4x 12 y = 2 x 2 4 x 12 Complete the square for 2x2 −4x12 2 x 2 4 x 12 Tap for more steps Use the form a x 2 b x c a x 2 b x c, to find the values of a a, b b, and c c a = 2, b = − 4, c = 12 a = 2, b = 4, c = 12 Consider the vertex form of a parabola




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Answer by LKHolland(3) (Show Source) You can put this solution on YOUR website!Question What is the vertex of the equation y=x^212x4 Found 2 solutions by MathLover1, josgarithmetic Answer by MathLover1() (Show Source) You can put this solution on YOUR website!You can put this solution on YOUR website!



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What are the xintercepts of the graph of f?Answer (1 of 4) The question is open to interpretation If the original parabola is y² = x5 or y = (x5)² and a translation is applied of (x2,y4) then new equations are (y4)² = x7 or y4 = (x7)² And the vertex in either case is now = (74)Show steps y=x^212x4 Calculus!!




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Question solve by vertex form y = x^26x12 y = 4x^224x11 Answer by stanbon (757) ( Show Source ) You can put this solution on YOUR website!Answer (1 of 6) x²4x= 4y12 x²4x4= 4y124 (x2)²= 4(y4) { (x2)²=4(1)(y4)} Vertex = (2,4) Focus =( 2,3) Equation of directrix ;Adding 12 on both sides;




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Don't Memorise The vertex form of a quadratic function is given by y = a(x − h)2 k, where (h,k) is the vertex of the parabola We can use the process of Completing the Square to get this into the Vertex Form y = x2 − 4x 2 → y −2 = x2 − 4x (Transposed 2 to the Left Hand Side) Now we ADD 4 from each side to complete the squareLog On Algebra in Finance Algebra Solvers Solvers Lessons Lessons Answers archive Answers You can put this solution on YOUR website! nt The length of side A C is labeled as 5 x minus 22 The length of side A B is labeled as 4 x minus 10 The length of side B C is labeled as 3 x plus 2 Enter your answer in the box y = An isosceles triangle A B C with horizontal base B C and vertex A is above the base Side A C and C B are labeled with single tick mark



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Complete the square by adding and subtracting the suitable value Divide the 4x by 2 and take its square = (4/2) 2 = 2 2 = 4 Use the calculated value to complete the square = x 2 4x 4 4 1 = 1(x 2) 2 3 How to find the vertex?Y=x^212x=4 (Please show your work to show me the steps to get to the right answer) 2 Use the quadratic formula to solve the equation x^27x6=0 (Please show your work to show me the steps to get to the right answer ) So, the xintercepts are 6 and 2 (b) The yintercept The yintercept is the point where the xcoordinate is ZERO So, replace x with 0 to get \(y=0^2−4(0)−12\) Evaluate \(y=−12\) So, the yintercept is 12 (c) Coordinates of the vertex Take y = x² − 4x − 12 Rewrite as y = x² − 4x 4 − 12 4 the net effect of adding 4 and



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Y X 2 4x 32 Axis Of Symmetry 2 Vertex 2 36 X Intercepts 4 0 8 0 How Dose The Axis Of Symmetry Relate To Enotes Com
##y = x^24x12## Part 1 xintercepts The xintercepts occur at point son the function where ##y=0## So, we need to solve ##x^24x12 = 0## The left side factors fairly easily into ##(x6)(x2)=0## So solution occur when ##x6 = 0 rarr x=6## and ##x2= 0 rarr x=(2)## So the xintercepts are at ##(0,6)## and ##(0,2)## Part 2 vertex of theThe vertex of a parabola is located at (12, 1) The parabola also passes through the point (10, 5) 2x^26 C)2x^27x6 D) 2x^2 x6**** 2) what is the simplified form of (3x2)(4x3) use a table Answer y = x² 4x 12 When y = 0 x² 4x 12 = 0 x² 4x 12 = 0 (x 2)(x 6) = 0 x = 2 or x = 6 The xintercepts are 2 and 6 y = (x² 4x) 12 y




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then the xcoordinate of the vertex = y = 2x² 4x 12 is in standard form with a = 2, b= 4 and c = 12 = = 1 substitute x = 1 into the equation for y y = 2 (1)² 4 (1) 12 = 14 vertex = (1, 14 ) mitgliedd1 and 9 more users found this answer helpful heart outlinedSolve by vertex form You do not "solve" by vertex form You may "put the equation" into vertex form




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